Timeline for Can you hear the shape of a drum by choosing where to drum it?
Current License: CC BY-SA 3.0
24 events
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Jul 26, 2016 at 15:04 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
Changed image to https.
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Mar 9, 2016 at 16:59 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
added 528 characters in body
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Mar 9, 2016 at 10:13 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
Improved definition to deal unambiguously with degenerate eigenvalues.
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S Feb 24, 2016 at 14:22 | history | suggested | emiliocba |
Added a new tag
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Feb 24, 2016 at 14:00 | review | Suggested edits | |||
S Feb 24, 2016 at 14:22 | |||||
Feb 5, 2016 at 19:34 | comment | added | Emilio Pisanty | @Delio Oooooh, ok, that's an interesting sort of thing to ask. And yeah, it does sound like it should have connections. | |
Feb 5, 2016 at 19:10 | comment | added | Delio Mugnolo | @EmilioPisanty A good starting point, with a survey of earlier results and more numerical experiments than proofs is journals.cambridge.org/action/… | |
Feb 5, 2016 at 14:58 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
added 48 characters in body; edited title
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Feb 5, 2016 at 12:06 | comment | added | Emilio Pisanty | @Delio That's the first time I hear of that theory - have you got a good introduction to the topic? (Say, physicist-grade.) | |
Feb 5, 2016 at 11:02 | comment | added | Delio Mugnolo | Very nice question and I wonder whether there is any connection to the theory of spectral maximal partitions. | |
Feb 4, 2016 at 16:53 | answer | added | Emilio Pisanty | timeline score: 37 | |
Jan 6, 2016 at 0:11 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
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Jan 5, 2016 at 23:51 | answer | added | Carlo Beenakker | timeline score: 13 | |
Jan 5, 2016 at 19:31 | comment | added | Liviu Nicolaescu | If you know enough of the eigenfunctions you can recover the whole domain. | |
Jan 5, 2016 at 19:19 | comment | added | Emilio Pisanty | @LiviuNicolaescu The goal here is a global isometry, or lack thereof. If knowing the eigenfunctions locally gets you local knowledge of the metric, then that's interesting but it's not quite what I'm asking. | |
Jan 5, 2016 at 19:16 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
Clarified the question.
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Jan 5, 2016 at 19:15 | history | edited | Nik Weaver | CC BY-SA 3.0 |
you can hear the *sound* of a drum by hitting it anywhere
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Jan 5, 2016 at 19:12 | comment | added | Liviu Nicolaescu | By shape I understand the Riemann metric defining the Laplacian. In the case at hand the metric is Euclidean so there is not much to say. | |
Jan 5, 2016 at 18:54 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
added 92 characters in body
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Jan 5, 2016 at 18:49 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
Fixed reference. Added alternative description.
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Jan 5, 2016 at 16:38 | history | edited | Emilio Pisanty | CC BY-SA 3.0 |
deleted 7 characters in body
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Jan 5, 2016 at 16:38 | comment | added | Jason Starr | @LiviuNicolaescu: Should "the shape of that region $R$" be "the shape of $D$"? | |
Jan 5, 2016 at 16:36 | comment | added | Liviu Nicolaescu | If you know the spectrum of the Laplacian and the restrictions of the eigenfunctions to a tiny region $R\subset D$, then you can determine the shape of that region $R$. www3.nd.edu/~lnicolae/RandMorseSpecGeom.pdf | |
Jan 5, 2016 at 16:29 | history | asked | Emilio Pisanty | CC BY-SA 3.0 |