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May 11, 2016 at 14:18 vote accept Clark Kimberling
Jan 14, 2016 at 8:26 answer added Alexey Ustinov timeline score: 4
Jan 12, 2016 at 20:30 comment added Clark Kimberling Think of $d(x)$ as the deviance of x from its continued fraction, maximized by the golden ratio, with maximal value approximately $1.195955786017513596003474800021$. (One can also define upper and lower deviances, which are also maximized by the golden ratio.) I raised the question about the "mean deviance" because of the possibility that it doesn't exist; viz., is $d$ Lebesgue integrable?
Jan 5, 2016 at 11:41 comment added Alexey Ustinov Are there any reasons to study this constant?
Jan 5, 2016 at 6:04 comment added Alexey Ustinov The function $d(x)$ is continuous at any irrational $x$. So it is sufficient to know $d(x)$ for rational $x$.
Jan 4, 2016 at 14:50 history edited Clark Kimberling CC BY-SA 3.0
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Jan 4, 2016 at 14:42 history asked Clark Kimberling CC BY-SA 3.0