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Jan 4, 2016 at 20:10 comment added H A Helfgott To wit: if $f(x)$ decays like $exp(-x^r)$ as $x\to \infty$, then $M(\sigma+i\tau)$ cannot decay as fast as $exp(-c |\tau|)$ for any $c>\pi/2r$. (Well, unless $f$ is $0$ almost everywhere, obviously.)
Jan 4, 2016 at 13:49 history answered H A Helfgott CC BY-SA 3.0