Timeline for What is the first cohomology $H_{fppf}^{1}(X, \alpha_{p})$?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Mar 4, 2016 at 0:45 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Typo.
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| Jan 31, 2016 at 5:22 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Reorganised the argument a bit.
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| Jan 1, 2016 at 11:40 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Removed some confusion.
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| Jan 1, 2016 at 11:27 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Fun remark.
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| Jan 1, 2016 at 9:45 | comment | added | kiseki | @van Dobben de Bruyn: Thanks! Happy new year! | |
| Jan 1, 2016 at 9:09 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Clarification.
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| Jan 1, 2016 at 8:59 | comment | added | R. van Dobben de Bruyn | Right; it's a finite-dimensional $k$-vector space. Since $k$ is algebraically closed, it's therefore infinite (unless it's $0$). | |
| Jan 1, 2016 at 8:57 | history | edited | R. van Dobben de Bruyn | CC BY-SA 3.0 |
Formatting
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| Jan 1, 2016 at 8:52 | comment | added | kiseki | @van Dobben de Bruyn: Does this mean $H^{1}_{fppf}(X, \alpha_{p})$ is not a finite group ? | |
| Jan 1, 2016 at 8:48 | history | answered | R. van Dobben de Bruyn | CC BY-SA 3.0 |