Timeline for Convolutions and Toeplitz Operators
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 1, 2010 at 5:11 | history | edited | Leandro | CC BY-SA 2.5 |
deleted 4 characters in body
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| Jul 1, 2010 at 2:44 | history | edited | Leandro | CC BY-SA 2.5 |
added 430 characters in body
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| Apr 27, 2010 at 10:35 | history | edited | Leandro | CC BY-SA 2.5 |
added 2 characters in body; added 2 characters in body; added 12 characters in body
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| Apr 27, 2010 at 10:29 | history | edited | Leandro | CC BY-SA 2.5 |
deleted 245 characters in body; added 21 characters in body; added 68 characters in body
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| Apr 27, 2010 at 9:55 | history | edited | Leandro | CC BY-SA 2.5 |
added 23 characters in body; added 1 characters in body; added 8 characters in body; added 4 characters in body
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| Apr 27, 2010 at 9:17 | comment | added | Thomas Kragh | but now 2 implies a stronger 2 where $K=0$. Indeed $\sum g(x-z)g(z-y) = \sum g(x+y-z)g(z)$ which for fixed $x+y$ can have $x-y$ going to infinity, so the left hand side is always zero. | |
| Apr 27, 2010 at 8:43 | comment | added | Leandro | Sorry for the mistypes. I edited the question correcting it. So $g(x,y)$ should be $g(x-y)$ and $x$ and $y$ in fact, belongs to $\mathbb Z^d$. | |
| Apr 27, 2010 at 8:37 | history | edited | Leandro | CC BY-SA 2.5 |
added 2 characters in body; edited body
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| Apr 27, 2010 at 8:23 | comment | added | Thomas Kragh | What is $x-z$ when $z \in \mathbb{Z}^d$ and $x\in \mathbb{Z}$? and if $d\neq 2$ what is $g(x,y)$? If you mean $x,y\in \mathbb{Z}^d$ then again what is $g(x,y)$ for any $d$? | |
| Apr 27, 2010 at 8:02 | history | asked | Leandro | CC BY-SA 2.5 |