Timeline for Quotient of a smooth curve by a finite group and differentials
Current License: CC BY-SA 3.0
8 events
when toggle format | what | by | license | comment | |
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Dec 25, 2015 at 18:34 | comment | added | Lisa S. | @NoamD.Elkies: I just mean that the action is "defined over $k$" as you say, i.e., $X$ is a $k$-scheme, $G$ is also a $k$-scheme (a "constant" one), there is a $k$-scheme morphism $G \times_k X \rightarrow X$ such that blah blah blah, etc. | |
Dec 25, 2015 at 4:24 | comment | added | Noam D. Elkies | What does it mean for the action of $G$ on a curve to be "$k$-linear"? Or do you just mean that the action is defined over $k$? | |
Dec 24, 2015 at 19:30 | vote | accept | Lisa S. | ||
Dec 24, 2015 at 16:17 | answer | added | Jason Starr | timeline score: 8 | |
Dec 24, 2015 at 10:48 | answer | added | Niels | timeline score: 7 | |
Dec 24, 2015 at 8:09 | comment | added | Philip Engel | Yes, the pullback of a form from the quotient is invariant, so you need only check that an invariant form is the pullback of a form. Given an invariant form on $X$, one can define a form locally on $Y$ away from the ramification locus by defining it as the value on one of the covering sheets. It is easy to check that this form extends holomorphically to all of $Y$. For instance, using Riemann-Hurwitz (or really just the local description of holomorphic maps $z\mapsto z^n$) to verify that the extension is holomorphic. | |
Dec 24, 2015 at 7:44 | answer | added | R. van Dobben de Bruyn | timeline score: 4 | |
Dec 23, 2015 at 21:40 | history | asked | Lisa S. | CC BY-SA 3.0 |