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Dec 24, 2015 at 11:43 answer added Geoff Robinson timeline score: 2
Dec 23, 2015 at 10:09 comment added R. Shhaied Sorry, Aut(H)≅Aut(G) implies H≅G?
Dec 23, 2015 at 10:00 history edited R. Shhaied CC BY-SA 3.0
Aut(H)≅Aut(G)
Dec 23, 2015 at 9:08 comment added Alain Valette Carmichael's conjecture states that the equation $\varphi(x)=n$ (where $n$ is given) never has a unique solution. This amounts to saying that the finite cyclic group $\mathbb{Z}/n\mathbb{Z}$ is never characterized by the order of its automorphism group.
Dec 23, 2015 at 9:07 comment added verret You need to be more precise about what you mean by $Aut(H)=Aut(G)$. Do you mean that $Aut(H)$ is isomorphic (as an abstract group) to $Aut(G)$?
Dec 23, 2015 at 7:45 history edited Todd Trimble
edited tags
S Dec 23, 2015 at 6:43 history suggested AHusain CC BY-SA 3.0
Finite in the question but cyclic in the title.
Dec 23, 2015 at 5:41 review Suggested edits
S Dec 23, 2015 at 6:43
Dec 23, 2015 at 4:28 history asked R. Shhaied CC BY-SA 3.0