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Timeline for Complexity of this minimization

Current License: CC BY-SA 3.0

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Dec 21, 2015 at 21:05 vote accept user66081
Dec 21, 2015 at 21:03 comment added user66081 I was missing the following bit. Write $\alpha = x^b$ and $\beta = x^{1-b}$, and note that $\alpha \beta = {const}$. Then $(\alpha + \beta) \mapsto |\log(\alpha/\beta)|$ is nondecreasing.
Dec 21, 2015 at 18:51 comment added Max Alekseyev Simpler explanation follows from the AM-GM inequality.
Dec 21, 2015 at 18:39 comment added Linus Hamilton Because $x^b+x^{1-b}=\left(\sqrt{x^{b}}-\sqrt{x^{1-b}}\right)^{2}+2\sqrt{x^{1}}$. Since $x^1$ does not depend on $b$, minimizing this is equivalent to minimizing $|\sqrt{x^{b}}-\sqrt{x^{1-b}}|$. Which is the same as getting $x^b$ and $x^{1-b}$ as close together as possible.
Dec 21, 2015 at 18:25 comment added user66081 If the sums of logs are to be as close as possible, the ratio $x^b / x^{1-b}$ should be close to one. Why is this the right condition?
Dec 21, 2015 at 17:39 history answered Linus Hamilton CC BY-SA 3.0