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Jean Duchon
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Yes if all matrices have the same rank. Your $x^*(\delta)$$x_*(\delta)$ is $A(\delta)^+b$ where $A^+$ is the Moore-Penrose pseudoinverse of $A$, which depends continuously on $A$ if (and only if) restricted to matrices of the same rank.

For the more general case, I don't know.

Yes if all matrices have the same rank. Your $x^*(\delta)$ is $A(\delta)^+b$ where $A^+$ is the Moore-Penrose pseudoinverse of $A$, which depends continuously on $A$ if (and only if) restricted to matrices of the same rank.

For the more general case, I don't know.

Yes if all matrices have the same rank. Your $x_*(\delta)$ is $A(\delta)^+b$ where $A^+$ is the Moore-Penrose pseudoinverse of $A$, which depends continuously on $A$ if (and only if) restricted to matrices of the same rank.

For the more general case, I don't know.

Source Link
Jean Duchon
  • 3.1k
  • 11
  • 17

Yes if all matrices have the same rank. Your $x^*(\delta)$ is $A(\delta)^+b$ where $A^+$ is the Moore-Penrose pseudoinverse of $A$, which depends continuously on $A$ if (and only if) restricted to matrices of the same rank.

For the more general case, I don't know.