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Dec 17, 2015 at 19:13 history edited Greg Martin CC BY-SA 3.0
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Dec 17, 2015 at 11:05 vote accept Jeffrey Shallit
Dec 17, 2015 at 7:16 comment added Denis Chaperon de Lauzières To get the (Z_{gamma}) independent, one probably also needs to assume linear independance of ordinates of zeros of zeta...
Dec 17, 2015 at 6:49 history edited Greg Martin CC BY-SA 3.0
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Dec 17, 2015 at 2:51 comment added Lucia You might need to change your explicit formula a bit -- there'll be $1/\zeta^{\prime}(\rho)$'s in the denominator. So like with the usual partial sums of the Mobius function, this would be a bit more painful to work with than the analogs for $\psi(x)$.
Dec 17, 2015 at 2:36 comment added Peter Humphries See chapter 15 of Montgomery and Vaughan's book; the methods there produce sign changes for $\psi(x)$, and the same methods would show that $f(x)/x^{3/2}$ changes sign infinitely often.
Dec 16, 2015 at 23:04 comment added Jeffrey Shallit Great! But what can be proved, if anything, unconditionally?
Dec 16, 2015 at 22:12 history answered Greg Martin CC BY-SA 3.0