Skip to main content
8 events
when toggle format what by license comment
Dec 22, 2015 at 20:09 comment added Igor Belegradek I was merely explaining that even when $S$ is simply-connected, there is no way to extend an arbitrary smoothing of $X_0$ to $X$. There is a similar phenomenon when $S$ is not simply-connected: For sufficiently large $n$ (probably $n>3$), there is a map $\phi$ from the set of homology $n$-spheres to the set of smooth structures on $S^n$ such that $\phi(\Sigma^n)$ is standard if and only if $\Sigma^n$ boudns a contractible manifolds. I suggest looking at Kervaire's paper on homology spheres.
Dec 22, 2015 at 15:37 comment added ε-δ You assume that S is simply connected and you should not.
Dec 18, 2015 at 16:48 comment added Igor Belegradek It is correct, if the boundary of $X$ is a homotopy sphere, which is how I apply it. Let $X_0$ be $X$ with small ball removed. The boundary of $X_0$ has two components: $S$ and $S_0$, where $S_0$ is the standard sphere. By excision the inclusion $i: S_0\to X_0$ is a homology isomorphism, and since everything is simply-connected, $i$ is a homotopy equivalence. By duality the inclusion $j: S\to X_0$ is also a homology isomorphism. If $S$ is simply-connected, then $j$ is a homotopy equivalence.
Dec 18, 2015 at 16:23 comment added ε-δ By the way, you say "removing a small ball from the interior of the contractible manifold gives an h-cobordism". Are you sure (I do not think it is correct).
Dec 17, 2015 at 15:29 comment added Igor Belegradek You might be interested in arxiv.org/abs/1406.1735.
Dec 17, 2015 at 15:08 vote accept ε-δ
Dec 17, 2015 at 15:07 comment added ε-δ Thank you very much. By the way, the question was not revised — it was understood wrongly.
Dec 16, 2015 at 21:58 history answered Igor Belegradek CC BY-SA 3.0