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Dec 21, 2015 at 12:24 comment added Boaz Tsaban Thanks for the answer! It immediately raises another question, posed seperately so as not to deprive you of answering the first question.
S Dec 15, 2015 at 10:48 history suggested Boaz Tsaban CC BY-SA 3.0
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Dec 15, 2015 at 10:43 vote accept Boaz Tsaban
Dec 15, 2015 at 10:42 review Suggested edits
S Dec 15, 2015 at 10:48
Dec 15, 2015 at 7:18 comment added Ashutosh I used to think that the symbol for reaping number was $\tau$!
Dec 15, 2015 at 7:17 history edited Ashutosh CC BY-SA 3.0
added 520 characters in body
Dec 15, 2015 at 7:00 comment added Boaz Tsaban I think I can see what you mean, that is, why $\operatorname{cov}(\mathcal{E})\le\mathfrak{r}$. Then the forcing part can be replaced by the consistency of $\mathfrak{r}<\mathfrak{d}$. But to be on the safe side, and for other readers, could you provide more details for the former assertion, and if exists, also a reference? (Also, any reason why the reaping number is denoted here $\tau$ and not $\mathfrak{r}$ as is more customary?)
Dec 15, 2015 at 6:54 history answered Ashutosh CC BY-SA 3.0