Timeline for Dimension of a commutative ring
Current License: CC BY-SA 3.0
8 events
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Jun 25, 2016 at 13:15 | history | edited | Sean Lawton | CC BY-SA 3.0 |
Editted formatting to make question easier to read.
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Dec 13, 2015 at 3:41 | answer | added | Todd Leason | timeline score: 2 | |
Dec 12, 2015 at 19:29 | comment | added | Jason Starr | I think that you did not understand the point of my comment. For a product of two rings, the prime spectrum (with the Zariski topology) is the disjoint union of the prime spectra of the factors. Thus, even if one factor ring fails to be Jacobson, if the factor ring with larger dimension is Jacobson, forming the quotient by the Jacobson radical will not change the dimension. | |
Dec 12, 2015 at 18:39 | history | edited | Anderia silva | CC BY-SA 3.0 |
edited tags
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Dec 12, 2015 at 18:38 | comment | added | Anderia silva | $R $ is not any special ring in general, such as a product of Jacobson rings. | |
Dec 12, 2015 at 18:22 | comment | added | Jason Starr | What if your ring is a product of a Jacobson ring, such as $\mathbb{C}[x,y]$ and a non-Jacobson ring, such as $\mathbb{C}[t]_{\langle t \rangle}$? Then what do you get for both sides of your inequality? | |
Dec 12, 2015 at 18:19 | review | First posts | |||
Dec 12, 2015 at 19:47 | |||||
Dec 12, 2015 at 18:16 | history | asked | Anderia silva | CC BY-SA 3.0 |