Timeline for Magic tesseract of order 3 composed of prime numbers
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 12, 2015 at 8:43 | comment | added | Natalia Makarova | My program has found the approximate solution: s3.postimg.org/6862y2rpf/tesseract3b.png Wrong complementary pairs: (10909, 65017), (41473, 34453), (42583, 33343), (17041, 58885), (39289, 36637), (72829, 3097) | |
| Dec 12, 2015 at 3:57 | comment | added | Gerry Myerson | @Per, in order for $a+b,a+2b,\dots,a+81b$ to be distinct prime numbers, $b$ has to be divisible by the product of all the primes less than 81. | |
| Dec 12, 2015 at 1:55 | comment | added | Natalia Makarova | Sorry. Clarification. Let there be given an arithmetic progression an = 3 + 5 (n-1), n = 1,2, ... 81. | |
| Dec 12, 2015 at 1:49 | comment | added | Natalia Makarova | As far as I know, found an arithmetic progression of 26 primes. | |
| Dec 12, 2015 at 1:41 | comment | added | Natalia Makarova | I know this method. Let there be given an arithmetic progression an = 3n + 5 (n-1), n = 1,2, ... 81 Compose magic tesseract of order 3 of the numbers of the arithmetic progression: 333 38 238 143 388 78 133 183 293, 98 208 303 358 3 248 153 398 58, 178 363 68 108 218 283 323 28 258, 128 193 288 343 33 233 138 383 88, 163 393 53 93 203 313 353 13 243, 318 23 268 173 373 63 118 213 278, 148 378 83 123 188 298 338 43 228, 348 8 253 158 403 48 103 198 308, 113 223 273 328 18 263 168 368 73 I believe that a solution can be found without an arithmetic progression of 81 primes. | |
| Dec 12, 2015 at 1:28 | comment | added | Per Alexandersson | Computer search reveals that there are no solutions with $a,b \leq 2000$. | |
| Dec 12, 2015 at 1:12 | history | answered | Richard Stanley | CC BY-SA 3.0 |
