Timeline for When does $\langle grg^{-1}|g\in G\rangle = \langle gsg^{-1}|g\in G\rangle$ imply $\langle r\rangle=\langle xsx^{-1}\rangle$?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 28, 2015 at 17:47 | comment | added | Geoff Robinson | I have written up something more careful. | |
| Dec 28, 2015 at 15:11 | comment | added | Will Sawin | @GeoffRobinson I don't understand all the details of the argument, perhaps you could expand it as an answer? | |
| Dec 11, 2015 at 3:08 | history | edited | Dave Witte Morris | CC BY-SA 3.0 |
corrected a typo
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| Dec 11, 2015 at 1:26 | history | answered | Will Sawin | CC BY-SA 3.0 |