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Dec 10, 2015 at 17:20 comment added Benjamin Steinberg If it exists, then it is unique since such an algebra must be basic and there is a unique basic algebra in each Morita class.
Dec 10, 2015 at 17:20 vote accept Ehud Meir
Dec 10, 2015 at 17:19 comment added Benjamin Steinberg If $K$ is $\mathbb Q$ and $A$ is the quaternion division algebra over $\mathbb Q$, then $A$ is already basic and has trivial Jacobson radical. No algebra Morita equivalent to $A$ has quotient by is radical commutative because all such are semisimple and $A$ is not Morita equivalent to a commutative algebra..
Dec 10, 2015 at 17:09 history edited Ehud Meir CC BY-SA 3.0
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Dec 10, 2015 at 17:03 answer added Theo Johnson-Freyd timeline score: 4
Dec 10, 2015 at 16:11 history asked Ehud Meir CC BY-SA 3.0