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Dec 11, 2015 at 19:00 comment added Yasha Actually tracefree does not really help since at least in the formulation above one could restrict wlog to SU(n) connections. So at least for the formulation above the answer looks to be: no there is no growth.
Dec 11, 2015 at 15:16 comment added Yasha As I posted my last comment I realized you were probably right, but it was too late to change. Anyway as the question as stated now there does not seem to be a problem?
Dec 11, 2015 at 15:12 comment added Sebastian Goette Operator norm with respect to which norm on $E^n$, then? If you take the Hermitian norm induced by the direct product metric, the operator norm stays constant - if not, feel free to send me a proof. On the other hand, Chern numbers $(c_{k_1}(E^n)\cdots c_{k_\ell}(E^n))[X]$ can be estimated using the product of the operator norm and a polynomial in $n\mathrm{rk} E$ depending on the numbers $k_1,\dots, k_\ell$. Hence, they may grow even though the operator norm does not.
Dec 11, 2015 at 15:00 comment added Yasha I think this is just a difference of what we mean by operator norm, for me this is: $\mathfrac{||Av}||}{||v||}$, for a direct sum operator the operator norm adds.
Dec 10, 2015 at 14:30 comment added Yasha Sebastian the original version of the question was also ok, since the operator norm if the direct sum connection is exactly double. Adding tracefree does not substantially change the question, but I keep this change since ultimately this is what I want.
Dec 9, 2015 at 16:47 history edited Yasha CC BY-SA 3.0
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Dec 9, 2015 at 13:33 history edited Yasha CC BY-SA 3.0
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Dec 8, 2015 at 16:38 history edited Yasha CC BY-SA 3.0
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Dec 8, 2015 at 14:00 comment added Sebastian Goette Btw, have you read Gromov's article? Somewhere in section 4-6 he does something looking very similar to your question.
Dec 8, 2015 at 12:51 history edited Yasha CC BY-SA 3.0
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Dec 7, 2015 at 18:53 comment added Sebastian Goette There is a paper by Narasimhan and Ramanan that answers your second question - every connection can be pulled back from the standard connection on the tautological bundle over the Grassmann manifold $G_{r,N}(\mathbb C)$, provided $N$ is large enough ($N$ is determined by $r$ and $\dim X$ alone, if I remember correctly).
S Dec 7, 2015 at 18:09 history suggested Silvia Ghinassi CC BY-SA 3.0
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Dec 7, 2015 at 17:45 review Suggested edits
S Dec 7, 2015 at 18:09
Dec 7, 2015 at 17:04 history asked Yasha CC BY-SA 3.0