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Wojowu
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The problem is indeed misquoted. Here is the correct statement:

If a polynomial $P(x)$ with rational coefficients has at least three simple zeros then the equation $y^2z^3=P(x)$ has only finitely many solutions in integers $x,y,z$ with $yz\neq 0$.

(copied verbatim from the text) The paper can be found here.

The problem is indeed misquoted. Here is the correct statement:

If a polynomial $P(x)$ with rational coefficients has at least three simple zeros then the equation $y^2z^3=P(x)$ has only finitely many solutions in integers $x,y,z$ with $yz\neq 0$.

(copied verbatim from the text)

The problem is indeed misquoted. Here is the correct statement:

If a polynomial $P(x)$ with rational coefficients has at least three simple zeros then the equation $y^2z^3=P(x)$ has only finitely many solutions in integers $x,y,z$ with $yz\neq 0$.

The paper can be found here.

Source Link
Wojowu
  • 28.2k
  • 3
  • 103
  • 185

The problem is indeed misquoted. Here is the correct statement:

If a polynomial $P(x)$ with rational coefficients has at least three simple zeros then the equation $y^2z^3=P(x)$ has only finitely many solutions in integers $x,y,z$ with $yz\neq 0$.

(copied verbatim from the text)