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Dec 5, 2015 at 18:37 vote accept MathStudent
Dec 5, 2015 at 14:30 history edited Jim Humphreys CC BY-SA 3.0
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Dec 5, 2015 at 10:35 comment added MathStudent @humphreys: I added the definition in the question. This is the definition in the steinberg's yale lectures. But i still do not understand why the $h_{\alpha}(t)$ is not diagonal. Thanks again for your help.
Dec 4, 2015 at 22:15 comment added Jim Humphreys @dulal: The choice of a Chevalley basis doesn't change the fact that $h_\alpha(t)$ is diagonal, but your definition of $x_\alpha(t)$ in the special case isn't correct. How are you defining $x_\alpha(t)$ in general?
Dec 4, 2015 at 17:21 comment added MathStudent @ humphreys: The chevellay basis I am using is in section 11.2.5 of Cartar's book ' Simple groups of Lie type'. The definition of the root space that I am using is in the yale lectures of steinberg which is in math.ucla.edu/~rst/YaleNotes.pdf
Dec 4, 2015 at 17:19 history edited Jim Humphreys CC BY-SA 3.0
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Dec 4, 2015 at 17:12 history answered Jim Humphreys CC BY-SA 3.0