Timeline for Exact formula for $\sum_{n=0}^{+\infty}\frac1{n^2+1}$
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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Nov 26, 2022 at 21:37 | history | edited | Todd Trimble | CC BY-SA 4.0 |
cot --> coth
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Dec 1, 2015 at 12:07 | comment | added | Fedor Petrov | oh, I did not know this trick with polynomial | |
Dec 1, 2015 at 11:32 | comment | added | Pietro Majer | (no: I've just found Herglotz trick on line) | |
Dec 1, 2015 at 11:24 | comment | added | Pietro Majer | Just to complete the picture, the expansion of the cotangent can be obtained by logarithmic differentiation from the infinite product for $\sin(\pi x)$, and the infinite product for $\sin(\pi x)$ can be obtained as dominated limit on the (easily computed) complete factorization of the polynomials $(1+iz/n)^n-(1-iz/n)^n$, that converge to $e^{iz}-e^{-iz}=2i\sin(z)$ (Is this Herglotz' proof?) | |
Dec 1, 2015 at 7:48 | history | edited | Fedor Petrov | CC BY-SA 3.0 |
added 965 characters in body
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Dec 1, 2015 at 5:59 | comment | added | Fedor Petrov | Indeed, but this works for all rational functions. | |
Dec 1, 2015 at 0:14 | comment | added | Alexandre Eremenko | Yes, but he asked to sum $f(n)$ with a more general class of functions $f$. | |
S Nov 30, 2015 at 22:52 | history | suggested | CommunityBot | CC BY-SA 3.0 |
Corrected two typos.
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Nov 30, 2015 at 22:45 | review | Suggested edits | |||
S Nov 30, 2015 at 22:52 | |||||
Nov 30, 2015 at 21:58 | history | answered | Fedor Petrov | CC BY-SA 3.0 |