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Dec 1, 2015 at 9:17 comment added Sebastian Goette The map $F$ in the edit is a bundle diffeo, but it does not intertwine the $SO(n)$-actions. You can get that if $n$ is odd by reversing the sign of all basis vectors. You cannot get it in general if $n$ is even because the Euler class would change its sign. However, the union of the two principal bundles become an $O(n)$ bundle. If you twist a $Spin(n)$-principal bundle with $Pin(n)$, you get a $Pin(n)$ principal bundle with an induced connection. You can still associate a spinor bundle with connection, and the second connected component becomes a $Spin(n)$ principal bundle for $o_2$.
Nov 29, 2015 at 9:49 history edited uro CC BY-SA 3.0
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Nov 28, 2015 at 21:01 answer added Sebastian Goette timeline score: 1
Nov 28, 2015 at 17:31 history asked uro CC BY-SA 3.0