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Apr 15, 2016 at 16:36 comment added Vladimir Ideally some kind of characterization would be good, or at least an interesting sufficient condition. But anything interesting would be interesting! And at this point would suffice for being an acceptable answer.
Apr 15, 2016 at 12:00 comment added Uri Bader Could you please try to specify what do you mean by "when"? What kind of answer do you expect?
S Dec 4, 2015 at 8:39 history bounty ended CommunityBot
S Dec 4, 2015 at 8:39 history notice removed CommunityBot
Nov 30, 2015 at 0:32 history edited Vladimir CC BY-SA 3.0
Changed title slightly, according to comment by user
Nov 26, 2015 at 14:51 comment added Lee Mosher Perhaps "Cartesian square root" would be a better terminology.
S Nov 26, 2015 at 7:03 history bounty started Vladimir
S Nov 26, 2015 at 7:03 history notice added Vladimir Draw attention
Nov 24, 2015 at 15:15 comment added Vladimir Thanks again Anthony. And yes - my choice of title is a little confusing.
Nov 24, 2015 at 9:10 comment added Anthony Quas The terminology "square root" is slightly difficult because Ornstein used it to mean (for $\mathbb Z$ actions) a transformation $S$ such that $S^2=T$. For i.i.d., this seems straightforward as you say (just using entropy)
Nov 24, 2015 at 8:04 comment added Vladimir Thanks! For amenable groups (at least) it seems like it should be possible to take the square root of i.i.d. actions. I wonder if more can be said.
Nov 24, 2015 at 6:16 comment added Anthony Quas If the $X$ action is ergodic, then the $Y$ action must be weak-mixing and hence the $X$ action must be weak-mixing. (That is you cannot find a square root like this if the $X$ action is ergodic but not weak-mixing).
Nov 24, 2015 at 5:52 history asked Vladimir CC BY-SA 3.0