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Timeline for Existence of a continuous section

Current License: CC BY-SA 3.0

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Jul 23, 2017 at 18:51 vote accept Jérémy Blanc
Nov 25, 2015 at 19:22 comment added Ramiro de la Vega You could consider $f^{-1}$ as a multivalued function from $Y$ to $X$ and then look at the various "continuous-selection-theorems" out there. For instance, if $f:[0,1] \to [0,1]$ is an open suryection and $f^{-1}(y)$ is compact for each $y$, then you have a continuous section (we don´t need to assume that $f$ is continuous or that $f^{-1}(y)$ is connected).
Nov 22, 2015 at 6:32 answer added Qiaochu Yuan timeline score: 8
Nov 22, 2015 at 2:23 answer added Paul Fabel timeline score: 12
Nov 21, 2015 at 23:28 review Close votes
Nov 22, 2015 at 19:50
Nov 21, 2015 at 23:16 comment added Jérémy Blanc Thanks for the nice comment. I did not know about this result. Are there some examples where $Y=[0,1]$ ?
Nov 21, 2015 at 23:12 comment added Olivier Bégassat The hairy ball theorem says that there is no section to the unit sphere bundle over the $2$-sphere : $US^2\to S^2$.
Nov 21, 2015 at 23:02 history asked Jérémy Blanc CC BY-SA 3.0