Timeline for Looking for (information about) long diamonds
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 1, 2015 at 17:15 | vote | accept | Gerhard Paseman | ||
| Dec 1, 2015 at 17:15 | comment | added | Gerhard Paseman | Thank you for the answer. Gerhard "Looking Forward To Christmas Problems" Paseman, 2015.12.01. | |
| Nov 21, 2015 at 20:12 | comment | added | Gerhard Paseman | How do we know continuity applies here? If you can replace x and y by x_p and y_p and show given epsilon that for all p large enough norm(x_p + y_p) \gt 2 - epsilon, then I will give you that the limit is no smaller than 2. Right now it is unclear if a scalar times your x and a related epsilon modification of your y will work. Gerhard "Skeptical LOL Cat Demands Proof" Paseman, 2015.11.21 | |
| Nov 21, 2015 at 17:51 | comment | added | Suvrit | Moreover, for $p=\infty$, we actually have $C_p=2$, as the example $x=[1,\ {-1}]$, $y=[1,\ 0]$ shows, so in particular we cannot have $\lim_p C_p < 2$. | |
| Nov 21, 2015 at 16:49 | history | edited | Suvrit | CC BY-SA 3.0 |
edited to prettify.
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| Nov 20, 2015 at 19:53 | history | edited | Suvrit | CC BY-SA 3.0 |
fixed link; wonder why links are getting messed up by themselves!
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| Nov 20, 2015 at 19:15 | history | edited | Suvrit | CC BY-SA 3.0 |
fixed link
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| Nov 20, 2015 at 18:58 | comment | added | Gerhard Paseman | At the moment "this note here" points to the Wikipedia page ( same as the other link ). Did you mean something else? Gerhard "Semantically Challenged By Indirect Reference" Paseman, 2015.11.20 | |
| Nov 20, 2015 at 18:52 | history | answered | Suvrit | CC BY-SA 3.0 |