Skip to main content
5 events
when toggle format what by license comment
Nov 23, 2015 at 9:47 comment added Michael Gaussians will not work. If they are Gaussian they answer to your question is no, if the pointwise limit of the difference quotient exists then the variance must converge, You can see this via ptwise implies in distribution implies cnvgs of characteristic fctns implies cnvgs of variance.
Nov 21, 2015 at 5:15 vote accept mcsanchez
Nov 21, 2015 at 5:09 comment added mcsanchez Thanks @Michael. It seems like Gaussians with mean $1/n$ and variance $1/n^2$ would work.
Nov 21, 2015 at 4:51 review Suggested edits
Nov 21, 2015 at 5:27
Nov 20, 2015 at 11:05 history answered Michael CC BY-SA 3.0