Timeline for Polynomial $g:\mathbb R^n \rightarrow\mathbb R^n$ with no critical point may have no root
Current License: CC BY-SA 3.0
6 events
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Nov 17, 2015 at 8:34 | history | edited | Jean Duchon | CC BY-SA 3.0 |
added 383 characters in body
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Nov 16, 2015 at 16:51 | comment | added | Jean Duchon | You're right, we need to chose $e^\pm$ non unit to satisfy integrability. I guess it's possible. Won't be enough anyway... | |
Nov 16, 2015 at 16:22 | comment | added | David E Speyer | But then you want to integrate their flows to make $X$, right? So you need the fields to be integrable. For the record, I agree that this sounds like a promising approach, I'm just trying to get the details right. | |
Nov 16, 2015 at 15:08 | comment | added | Jean Duchon | I didn't mean "vector fields" as differential operators, just as functions from $\mathbb R^2$ to itself... | |
Nov 16, 2015 at 12:53 | comment | added | David E Speyer | Why can you choose the fields to commute? | |
Nov 14, 2015 at 15:19 | history | answered | Jean Duchon | CC BY-SA 3.0 |