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May 12, 2010 at 20:40 vote accept Jan Weidner
Apr 23, 2010 at 15:03 comment added Pete L. Clark @George: this is true if the cardinality is uncountable. It is not true if the cardinality is countable, as I explained above. For instance the algebraic closure of $\mathbb{Q}$ is certainly not isomorphic to the algebraic closure of $\mathbb{Q}(t)$.
Apr 23, 2010 at 12:36 history answered Pete L. Clark CC BY-SA 2.5