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Nov 11, 2015 at 17:17 comment added Mudi Yes, I am sorry I meant to choose uniformly from the interior of circle. When $a=b$, the expression doesn’t look pretty (not to me at least) but the argument/procedure is simple enough (It’s described in Tuckwell’s Applications of Probability Theory). Anyway here it is. $f_X(x) = \frac{2x}{\pi r^2}( 2 \arccos(\frac{x}{2r}) - \frac{x}{r} \sqrt{ 1-{(\frac{x}{2r}) }^2} )$.
Nov 11, 2015 at 16:39 comment added Igor Rivin What do you get when $a=b?$
Nov 11, 2015 at 15:48 comment added Douglas Zare Do you mean the points are drawn from the interiors or from the boundaries?
Nov 11, 2015 at 15:37 answer added Joseph O'Rourke timeline score: 2
Nov 11, 2015 at 14:19 comment added Mudi Yes Gerry, I want to compute average degree of nodes placed, roughly, in a grid where adjacency defined in terms of distance. Problem arises in sensor networks.
Nov 11, 2015 at 12:05 comment added Gerry Myerson MO is for math research questions. Is there a research angle to this question?
Nov 11, 2015 at 11:04 history asked Mudi CC BY-SA 3.0