Timeline for Is Hessian operator self-adjoint on infinite dimensional environment?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 12, 2015 at 2:59 | vote | accept | Peter | ||
| Nov 11, 2015 at 15:58 | comment | added | Willie Wong | An important thing that Peter Michor didn't say: it is a lot more natural to think of the Hessian as a bilinear form, instead of as an operator. | |
| Nov 11, 2015 at 8:00 | history | answered | Peter Michor | CC BY-SA 3.0 |