Timeline for Countable subcover of half-open cylinders
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Nov 11, 2015 at 13:02 | comment | added | Pietro Majer | Yes, that's ok, but as it was stated, in the case $t=T$ we couldn't deduce that a finite family of balls covers $(t',t] \times B_r$ for some $t'<t$ (it should only be true "countable"). | |
| Nov 11, 2015 at 11:01 | history | bounty ended | zhoraster | ||
| Nov 11, 2015 at 11:01 | comment | added | zhoraster | I think there was no problem with the former argument, as $T$ belonged to $I$ obviously: the set $(t,T)\times B_r$ is empty for $t=T$. | |
| Nov 11, 2015 at 6:41 | comment | added | Pietro Majer | A minor correction was needed: the sentence after "Notice that" is not true for $t=T$, because $\{T\}\times B_r$ is not contained in $\mathbf{S}$ and shouldn't be covered by $\mathsf{D}$. I slightly modified the argument correspondingly. | |
| Nov 11, 2015 at 6:35 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 11, 2015 at 4:07 | vote | accept | zhoraster | ||
| Nov 10, 2015 at 22:55 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 10, 2015 at 22:49 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 10, 2015 at 22:39 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 10, 2015 at 22:25 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 10, 2015 at 22:17 | history | edited | Pietro Majer | CC BY-SA 3.0 |
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| Nov 10, 2015 at 21:27 | history | answered | Pietro Majer | CC BY-SA 3.0 |