Timeline for Can a general binary sextic form be put into the following form?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 28, 2016 at 23:13 | answer | added | user24815 | timeline score: 1 | |
| Dec 11, 2015 at 22:40 | answer | added | Robert Bryant | timeline score: 2 | |
| Nov 11, 2015 at 17:07 | answer | added | Abdelmalek Abdesselam | timeline score: 0 | |
| Nov 9, 2015 at 22:52 | comment | added | Stanley Yao Xiao | @NoamD.Elkies Is there any criterion which depends only on the coefficients of the sextic which determines whether such an involution exists? | |
| Nov 8, 2015 at 6:18 | comment | added | Noam D. Elkies | In general it can't be done even over ${\bf C}$, because the roots of such a sextic are paired by some involution of ${\bf P}^1$, and this happens only in a hyperplane in the space of all binary sextics. | |
| Nov 8, 2015 at 4:39 | history | asked | Stanley Yao Xiao | CC BY-SA 3.0 |