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Nov 9, 2015 at 18:50 vote accept David Carchedi
Nov 9, 2015 at 18:50 history edited David Carchedi CC BY-SA 3.0
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Nov 8, 2015 at 11:30 answer added Anton Fetisov timeline score: 10
Nov 8, 2015 at 8:01 comment added Fernando Muro For Eilenberg-MacLane spectra the second term does not appear.
Nov 8, 2015 at 7:18 comment added HJRW Could you explain your definitions please? I can't come up with candidates which make your first assertion correct in the case where $A=\mathbb{Z}$ and $n=1$.
Nov 8, 2015 at 5:33 history edited David Carchedi CC BY-SA 3.0
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S Nov 7, 2015 at 15:32 history suggested CommunityBot CC BY-SA 3.0
typos: autmorphisms -> automorphisms, eilgenberg -> eilenberg, maclane -> mac lane, principal -> principle
Nov 7, 2015 at 15:10 review Suggested edits
S Nov 7, 2015 at 15:32
Nov 7, 2015 at 8:23 comment added David Carchedi I see how both parts act. My question is how do we see this is everything?
Nov 7, 2015 at 8:19 comment added Qiaochu Yuan The $\text{Aut}(A)$ part is hopefully easy to see. The other part is the translation action of $K(A, n)$ on itself. So this is at least a natural guess. In general there's always a natural action of $G \rtimes \text{Aut}(G)$ on $G$ (as a set).
Nov 7, 2015 at 7:47 history asked David Carchedi CC BY-SA 3.0