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Nov 6, 2015 at 18:27 comment added Nicola Ciccoli I am not sure I get your idea, here. Quantum SU(n) tensored by $\mathbb C[\theta^{-1}]$ is already a "deformation", in the sense of being a $S^1$ family of $SU(n)$'s...
Nov 6, 2015 at 18:24 comment added Jeffrey Harrington Thanks a lot Nicola. And what is if we deform the quantum SU(n) also by a parameter (for example if we assume that K acts by a multiple of the identity)?
Nov 6, 2015 at 18:20 history answered Nicola Ciccoli CC BY-SA 3.0