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Timeline for Brownian motion in $n$ dimensions

Current License: CC BY-SA 3.0

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Dec 9, 2015 at 16:38 comment added Serguei Popov Probably yes, should be the starting point. But I'm travelling now, have no access to the book.
Dec 9, 2015 at 11:29 comment added SMS @SergueiPopov I will do that, thanks! One quick question, if I may: what does the $x$ in the expression $\mathbb{P}_x(\sup_{0 \leq s \leq t} R^{(n)}_s \geq y)$ denote? Does it mean that the particle starts at the point $x$?
Dec 2, 2015 at 21:31 comment added Serguei Popov I think it would be better to ask that to Borodin or Salminen :)
Dec 2, 2015 at 20:37 comment added SMS @SergueiPopov Very nice! I am very interested in learning more. Could you shed a little light on how one could prove this formula?
Nov 6, 2015 at 10:45 vote accept user82390
Nov 5, 2015 at 13:31 comment added Steve Huntsman A more general case is discussed here: mathoverflow.net/a/96719/1847
Nov 5, 2015 at 12:33 history answered Serguei Popov CC BY-SA 3.0