Timeline for How to solve the following system of diophantine equations?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 5, 2015 at 6:13 | comment | added | joro | @Turbo No, it is over the rationals. In general the number of solutions is finite (possibly only unless the third equation is identically zero). From the finite solutions find the natural ones. | |
| Nov 4, 2015 at 21:42 | comment | added | Turbo | @joro Is this over $\Bbb Z$? | |
| Nov 4, 2015 at 18:09 | comment | added | Robert Israel | That huge general expression is not particularly useful. Given particular coefficients, it's better to compute the Groebner basis or resultants using those coefficients. | |
| Nov 4, 2015 at 17:17 | comment | added | joro |
@Turbo here it is: q1:=[a1*x+b1*y+c1*z-d1,a2*x^2+b2*y^2+c2*z^2-d2,a3*x^3+b3*y^3+c3*z^3-d3];so:=solve(q1,[x,y,z]);
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| Nov 4, 2015 at 16:23 | comment | added | Turbo | could you post maple code as well? | |
| Nov 4, 2015 at 11:47 | history | answered | joro | CC BY-SA 3.0 |