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Nov 2, 2015 at 13:00 comment added Todd Trimble The way I remember it is largely based on this group-theoretic fact, but is stated a little differently: if the exponent of a finite abelian group equals its order, then the group is cyclic. A consequence being that a finite multiplicative subgroup of a field is cyclic.
Nov 2, 2015 at 12:13 history edited Gerry Myerson CC BY-SA 3.0
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Nov 2, 2015 at 11:46 history made wiki Post Made Community Wiki by Todd Trimble
Nov 2, 2015 at 10:58 comment added user41593 What do you mean by this? Take $y=x^{-1}$...
Nov 2, 2015 at 0:44 history answered Gerry Myerson CC BY-SA 3.0