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Dec 9, 2016 at 6:29 comment added user19475 This is also in Lemmermeyer's book "Reciprocity Laws".
Nov 2, 2015 at 11:46 history made wiki Post Made Community Wiki by Todd Trimble
Nov 2, 2015 at 1:47 comment added KConrad You need to clarify on what set you are acting by multiplication by $a \bmod m$. Multiplication by $a \bmod m$ on $\mathbf Z/m$ and on $(\mathbf Z/m)^\times$ need not have the same sign.
Nov 2, 2015 at 0:11 review Late answers
Nov 2, 2015 at 1:56
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Nov 1, 2015 at 23:53 history answered Brennan.Tobias CC BY-SA 3.0