Timeline for Quadratic twist of an elliptic curve given by Weierstrass model
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Mar 24, 2020 at 15:37 | comment | added | Watson | In the case $j(E)=0$, this page seems to provide some formulas for the quadratic twist. | |
| May 31, 2016 at 11:51 | history | edited | Daniel Loughran | CC BY-SA 3.0 |
added 2 characters in body
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| May 31, 2016 at 11:37 | comment | added | Joe Silverman | @DanielLoughran Thanks for noticing that typo in the answer. I changed the $x$ to $x^2$. | |
| May 31, 2016 at 11:36 | history | edited | Joe Silverman | CC BY-SA 3.0 |
fixed typo (x term should be x^2)
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| May 31, 2016 at 10:48 | comment | added | Daniel Loughran | Are you sure that you have the right equation for the quadratic twist? In your quoted exercise, there are no linear terms in x, and the quadratic terms in $x$ are $ax^2$ and $(a + D)x^2$. respectively. | |
| Oct 31, 2015 at 21:34 | history | edited | Joe Silverman | CC BY-SA 3.0 |
added 42 characters in body
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| Oct 31, 2015 at 14:05 | history | answered | Joe Silverman | CC BY-SA 3.0 |