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Oct 28, 2015 at 15:06 answer added David E Speyer timeline score: 4
Oct 28, 2015 at 14:04 vote accept Simon Rose
Oct 28, 2015 at 13:55 answer added Alexey Ustinov timeline score: 8
Oct 28, 2015 at 13:04 comment added Simon Rose ... Yeah, I just saw this. I can't believe that I didn't see that. You may as well put that down as an answer, I suppose?
Oct 28, 2015 at 12:55 comment added Alexey Ustinov Last identity is simple because $F(s)=\zeta(s)\zeta(s-1).$
Oct 28, 2015 at 12:40 history asked Simon Rose CC BY-SA 3.0