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Timeline for Classification of mapping tori

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Oct 10, 2016 at 5:00 comment added ThiKu For the second question (in brackets): if the bundles are just diffeomorphic and not bundle-isomorphic, then the mapping classes need not be conjugate. See mathoverflow.net/questions/241822/…
Apr 22, 2010 at 11:31 comment added Jeffrey Giansiracusa For a diffeotopy it is exactly the same short argument; topologically isotopic maps give homeomorphic bundles, and smoothly isotopic maps give diffeomorphic bundles. And in fact, reducing to the mapping class group is unnecessary. If f and g are isotopic then they are conjugate.
Apr 22, 2010 at 10:32 comment added Sam Nead I wonder if there is a subtle point lurking here... if $f_0$ and $f_1$ are isotopic (homotopic through homeomorphisms) then the two bundles will be homeomorphic. However, the question asked about diffeomorphism. This is not my area, so I don't see that a diffeotopy (homotopic through diffeomorphisms?) gives a diffeomorphism of bundles... It feels like the "quality" of the derivative of the time direction will be important?
Apr 22, 2010 at 9:00 history answered Jeffrey Giansiracusa CC BY-SA 2.5