Timeline for What is the difference between Grothendieck groups K_0(X) vs K^0(X) on schemes?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:57 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
|
|
| Sep 14, 2011 at 20:47 | history | edited | Ariyan Javanpeykar | CC BY-SA 3.0 |
added 505 characters in body
|
| Sep 14, 2011 at 20:38 | comment | added | Ariyan Javanpeykar | Thank you for your comment. I edited my answer accordingly. | |
| Sep 14, 2011 at 6:56 | comment | added | Michael | Something is slightly wrong here - $X$ is not quasi-compact (as you say), but all affine schemes $\mathrm{Spec}(A)$ are quasi-compact, so $X \ne \mathrm{Spec}(A)$. | |
| Apr 22, 2010 at 7:51 | history | edited | Ariyan Javanpeykar | CC BY-SA 2.5 |
I added another example
|
| Apr 22, 2010 at 7:31 | history | answered | Ariyan Javanpeykar | CC BY-SA 2.5 |