Skip to main content
3 events
when toggle format what by license comment
Apr 22, 2010 at 16:09 comment added Thomas Scanlon No, my functions are real valued. The function L has the form L(z) = a Re(z) + b Im(z) + c for some real numbers a, b and c. I am using the fact that if F(z) is complex analytic, then via the usual identification of C with R^2, the induced function G:R^2 -> R^2 given by (a,b) -> (Re(F(a+ib)),Im(F(a+ib))) is real analytic, a result one can see by expanding the Taylor series for F(a+ib).
Apr 22, 2010 at 12:09 comment added gowers My comment does not imply that the question isn't straightforward. I am struggling to understand your argument, however. Are your "real analytic" functions complex-valued? I should add that the fact that I am struggling to understand your argument is compatible with its being clear and correct.
Apr 22, 2010 at 7:26 history answered Thomas Scanlon CC BY-SA 2.5