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Oct 26, 2015 at 5:29 vote accept A.T.Saaki
Oct 26, 2015 at 1:30 answer added Allen Hatcher timeline score: 5
Oct 23, 2015 at 1:41 comment added A.T.Saaki Generally speaking, $[Homeo(S)]_{isotopy}$ with respect to some (bigger than 2) marked points is a non-tirvial group, see the definition of mapping class group in 'A primer on mapping class groups Version 5.0' by Benson Farb and Dan Margalit.
Oct 22, 2015 at 11:09 comment added Giovanni Moreno If there are no obstruction to the existence of a (non relative) isotopy connecting $h$ with the identity, then I guess that such an isotopy can be made into a relative to $P$ one. A relative isotopy is a special map from the cylinder $M\times [0,1]$ to $M$, sending each segment $\{p_i\}\times[0,1]$ to $p_i$, and I don't see why not a non relative one could not be suitably deformed to fulfill such a property. But this is just a guess.
Oct 22, 2015 at 8:55 history asked A.T.Saaki CC BY-SA 3.0