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Oct 22, 2015 at 13:20 comment added David Barnes Yes, the weak equivalences are the underlying weak equivalences. Thanks for the comprehensive answer.
Oct 22, 2015 at 13:16 vote accept David Barnes
Oct 21, 2015 at 19:27 history edited Tyler Lawson CC BY-SA 3.0
fixed #2.
Oct 21, 2015 at 16:44 history edited Tyler Lawson CC BY-SA 3.0
deleted 653 characters in body
Oct 21, 2015 at 16:35 history answered Tyler Lawson CC BY-SA 3.0