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Oct 21, 2015 at 17:51 comment added Sebastian Goette @Michael Albanese: yes, and I edited the answer.
Oct 21, 2015 at 17:50 history edited Sebastian Goette CC BY-SA 3.0
Small explanation added
Oct 21, 2015 at 16:56 comment added Michael Albanese I'm not sure what you mean by $rE$. You can write $E$ as $a + P$ where $P$ is a plane through the origin parallel to $E$ and $a \in E$, then the deformation retraction should be $ra + P$. Is that what you mean?
Oct 21, 2015 at 14:53 comment added Sebastian Goette Yes, I think so, but regard $E\subset\Bbbk^n$ as a plane, not as a set of points. Then the limit of $rE$ as $r\to 0$ is a plane through the origin, and not just $\{0\}$. Does that answer your question?
Oct 21, 2015 at 14:41 comment added Michael Albanese Is that really the deformation retraction?
Oct 21, 2015 at 9:38 vote accept Shi Q.
Oct 21, 2015 at 9:04 history answered Sebastian Goette CC BY-SA 3.0