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Nov 24 at 2:06 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 27 at 2:04 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jun 27 at 1:24 answer added Anton Petrunin timeline score: 0
Oct 21, 2015 at 12:18 review Close votes
Oct 22, 2015 at 14:14
Oct 21, 2015 at 11:55 comment added Benoît Kloeckner Smoothness at $O$ is the only restriction, right? If I understand notation correctly, for any metric of this kind the shortest path from the origin to a point is a ray (proof is the same as in proving that line segments are shortest paths in Euclidean space). Thus the function $f$ does not matter so much, except for its behavior near $0$. Unless you provide more information about what you expect your 'generalized space form' to look like, I don't think it is possible to give a good answer.
Oct 21, 2015 at 9:49 comment added pedro Yes, I require that. My goal is to have a suitable generalization of space forms.
Oct 21, 2015 at 8:50 comment added Robert Bryant Are you requiring that $M\cup\{O\}$ have a smooth structure such that $g$ is smooth at $O$?
Oct 21, 2015 at 8:21 history asked pedro CC BY-SA 3.0