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May 3, 2018 at 8:03 vote accept Matthias Wendt
May 2, 2018 at 11:59 answer added Vladimir Dotsenko timeline score: 3
Oct 21, 2015 at 7:06 comment added Matthias Wendt I think the module is finitely generated. First, the polynomial part is finitely generated over the symmetric polynomials (actually free of rank equal to the order of the corresponding symmetric group) and the alternating part is a finite-dimensional $\mathbb{F}_\ell$-vector space. This means $\mathfrak{F}(n)$ is finitely generated, but the ring of symmetric polynomials is noetherian.
Oct 20, 2015 at 17:57 comment added Todd Leason Do you happen to know if your submodule is finitely generated as module over the ring of sym. polynomials ?
Oct 20, 2015 at 15:08 history asked Matthias Wendt CC BY-SA 3.0