Skip to main content
6 events
when toggle format what by license comment
Oct 19, 2015 at 14:02 vote accept Hans
Oct 19, 2015 at 12:57 comment added Francesco Polizzi Uhm, it seems to me that for an isolated singularity the length coincides with the Milnor number, since the Milnor number is defined by taking the quotient of the local ring by the Jacobian ideal, right?
Oct 19, 2015 at 12:48 history edited Francesco Polizzi CC BY-SA 3.0
added 18 characters in body
Oct 19, 2015 at 12:47 answer added Francesco Polizzi timeline score: 3
Oct 19, 2015 at 11:39 comment added Jason Starr Yes, that is true. Consider the closed subscheme of a hypersurface that is defined by the Fitting ideal of the sheaf of relative differentials. The dimension of this closed subscheme is upper semicontinuous, so the parameter point $[X]\in \mathbb{P}(V)$ cannot be in the Zariski closure of the closed locus parameterizing hypersurfaces whose singular scheme has positive dimension. For nodal hypersurfaces, the length of the singular scheme is precisely the number of nodes, whereas for $k$-singular schemes, it is at least $k$. Finally, the length is upper semicontinuous.
Oct 19, 2015 at 11:04 history asked Hans CC BY-SA 3.0