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The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is classical Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

 
  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.

    There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.

     
  • $Y\prec X$ in convex stochastic order, i.e. $E[f(Y)]\le E[f(X)]$ for any convex function $f$.

    $Y\prec X$ in convex stochastic order, i.e. $E[f(Y)]\le E[f(X)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is classical Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

 
  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.
     
  • $Y\prec X$ in convex stochastic order, i.e. $E[f(Y)]\le E[f(X)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is classical Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.

  • $Y\prec X$ in convex stochastic order, i.e. $E[f(Y)]\le E[f(X)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

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zhoraster
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The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is a classical result, called Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.
  • $X\prec Y$$Y\prec X$ in convex stochastic order, i.e. $E[f(X)]\le E[f(Y)]$$E[f(Y)]\le E[f(X)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is a classical result, called Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.
  • $X\prec Y$ in convex stochastic order, i.e. $E[f(X)]\le E[f(Y)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is classical Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.
  • $Y\prec X$ in convex stochastic order, i.e. $E[f(Y)]\le E[f(X)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).

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zhoraster
  • 1.5k
  • 11
  • 24

The condition proposed by Nate Eldredge is not only necessary, but also sufficient. This is a classical result, called Strassen's theorem:

Theorem For integrable random variables $X$ and $Y$ the following is equivalent:

  • There exist $\hat X \overset{d}{=} X$ and $\hat Y \overset{d}{=} Y$ such that $E[\hat X | \hat Y] = \hat Y$.
  • $X\prec Y$ in convex stochastic order, i.e. $E[f(X)]\le E[f(Y)]$ for any convex function $f$.

Note that the formulation in Strassen's paper differs from this one (and Strassen attributed it himself to Hardy-Littlewood-Polya-Blackwell-Stein-Sherman-Cartier-Fell-Meyer). In the present form it is given e.g. in Ruschendorf (Theorem 6 for $i=2$).