Timeline for Number of intervals needed to cross, Brownian motion
Current License: CC BY-SA 3.0
5 events
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Oct 17, 2015 at 12:08 | history | edited | Nate River | CC BY-SA 3.0 |
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Oct 17, 2015 at 12:06 | comment | added | Nate River | @DouglasZare You are right. Thanks for pointing this out. | |
Oct 17, 2015 at 11:58 | comment | added | Douglas Zare | The intersection of $E_{j,n}$ with $E_{j+1,n}$ means that the Brownian motion hits $0$ on both of these intervals, not that it hits $0$ at the intersection of the intervals. This argument is not correct. By the way, the upper limit in the question is $2^{2n}$ rather than $2^{2^n}$. | |
Oct 17, 2015 at 11:14 | review | First posts | |||
Oct 17, 2015 at 11:47 | |||||
Oct 17, 2015 at 11:11 | history | answered | Nate River | CC BY-SA 3.0 |